9h^2+60h+100=0

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Solution for 9h^2+60h+100=0 equation: 



9h^2+60h+100=0

a = 9; b = 60; c = +100;
Δ = b2-4ac
Δ = 602-4·9·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{-60}{18}=-3+1/3$

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